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Q 1.

In a military camp, the ration was stored for 660 militants at the rate of 800 grams per militant for 45 days. After 10 days some militants came from another camp. As a result the remaining ration got finished only in 15 days at the rate of 1400 grams per militant. Find the number of coming militants. (approx value)

A) 
105
B) 
220
C) 
90
D) 
80
Answer & Explanation Answer:
220


Explanation:
Remaining time = (45 – 10) = 35 days Present no. of militants = 660

Let the number of coming militants be x.

Then, total militants = (660 + x) If x militants would not come,

660 militants would eat the remaining ration at a rate of 800 gram per militant in 35 days ...(i)

Let (660 + x) militants eat the remaining ration at the rate of 1400 grams per militant in 15 days.

By the chain rule method, we get M1R1D1 = M2R2D2

∴    660 × 800 × 35 = (660 + x) × 1400 × 15

or, (660 + x) = 660 × 800 × 35
1400 × 15

or,  660 + x = 880 or,  x = 880 – 660 = 220.

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MCQ Type: SSC CHSL, Work And Time

Q 2.

21 men can do a piece of work in 25 days working 10 hours a day, then how many men are required to complete the work in 15 days by working 7 hours per day?

A) 
45 men
B) 
47 men
C) 
50 men
D) 
54 men
Answer & Explanation Answer:
50 men


Explanation:

To solve this quesiton, we can apply the chain rule method

M1 × D1 × H1 = M2 × D2 × H2

Given, M1 = 21 men, D1 = 25 days, H1 = 10 hours

M2 = ?, D2 = 15 days, H2 = 7 hours

M2 = M1 × D1 × H1
D2 × H2

 

= 21 × 25 × 10  = 50 men
15 × 7

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MCQ Type: SSC CHSL, Quantitative Aptitude, Work And Time

Q 3.

If 6 women can reap 60 hectares in 24 days, then how many hectares can 36 women reap in 30 days?

A) 
300
B) 
350
C) 
400
D) 
450
Answer & Explanation Answer:
450


Explanation:

Let the required number of hectares be z. Then,

More women, More hectares                       (Direct proportion)
More days, More hectares                       (Direct proportion)

Women 6 : 36 }  :: 60 : z
Days 24 : 30

 

z = 60 x 36 x 30  = 450 hectares.
6 x 24

Hence, option D is correct.

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MCQ Type: SSC CHSL, Quantitative Aptitude, Work And Time

Q 4.

If 3 men and 4 boys together earn Rs. 264 in 8 days and 2 men and 3 boys together earn Rs. 184 in the same time, then in how many days will 6 men and 7 boys together earn Rs. 315 ?

A) 
5 days
B) 
6 days
C) 
9 days
D) 
10 days
Answer & Explanation Answer:
5 days


Explanation:

Given, 3 men and 4 boys together earn Rs. 264 in 8 days and 2 men and 3 boys together earn Rs. 184 in the same time

Now, according to the Chain Rule formula,

M1D1W2 = M2D2W1

where, M = No. of person, D = No. of days, W = Amount of work

⇒  (3M + 4B) × 8 × 184 = (2M+ 3B) × 8 × 264

⇒  3M = 7B        ...(i)

Let the no. of days 6 men and 7 boys will work together to earn Rs. 315 be x

(6M + 7B) × x × 184 = (2M + 3B) × 8 × 315

Substituting the relation between men and boys from equation (i) in above equation,

⇒  (14B + 7B) × x × 184 =

( 14 B + 3B )  × 8 × 315
3

⇒  21B × x × 184 = 23B × 8 × 105

⇒  x = 5

Thus, the no. of days 6 men and 7 boys will work together to earn Rs. 315 is 5.

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MCQ Type: SSC CHSL, Quantitative Aptitude, Work And Time

Q 5.

A person takes 8 minutes to type a page. If from 1 : 00 pm to 2 : 00 pm, 1710 pages are to be typed, how many persons should be employed for this job?

A) 
207
B) 
221
C) 
249
D) 
None of these
Answer & Explanation Answer:
None of these


Explanation:

M1 T1 W2 = M2 T2 W1

M1 = 1, T1 = 8 mins, W1 = 1 page

M2 = ?, T1 = 60 min (1 pm to 2pm), W2 = 1710

∴   M2 = 1 × 8 × 1710  = 228
60 × 1

 

Hence, 228 persons should be employed.

Hence, option D is correct.

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MCQ Type: SSC CHSL, Quantitative Aptitude, Work And Time

Q 6.

Cost of 24 bats and 32 sticks is Rs. 5,600. What is the price of 3 bats and 4 sticks

A) 
Rs. 1,400
B) 
Rs. 2,800
C) 
Rs. 700
D) 
Data inadequate
Answer & Explanation Answer:
Rs. 700


Explanation:
C.P. of 1 bat and 1 stick is x and y respectively

∴  24x + 32y = 5600

Dividing both sides by 8, we have
3x + 4y = 700.

Hence, option C is correct.

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MCQ Type: Quantitative Aptitude, SSC CHSL, Work And Time

Q 7.

If 16 men or 20 women can do a piece of work in 25 days, in what time will 28 men and 15 women do it ?

A) 
14 2 days
7
B) 
33 1 days
3
C) 
18 3 days
4
D) 
10  days
Answer & Explanation Answer:
10  days


Explanation:

16 M ≡ 20 W

Therefore, 1 men ≡ 5 women
4

Similarly, 28 men  ≡

 28 × 5  women  =  35 women
4

∴   28 men + 15 women ≡ 50 women Now applying the chain rule formula, we get

M1D1 = M2D2

M1 = 20 women, D1 = 25 days   and    M2 = 50 women, D2 = ?

D2 = 20 × 25  = 10 days
50

Hence, option D is correct

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MCQ Type: Quantitative Aptitude, Work And Time

Q 8.

4 goats or 6 sheeps can graze a field in 50 days. 2 goats and 9 sheeps can graze the field in

A) 
100 days
B) 
75 days
C) 
50 days
D) 
25 days
Answer & Explanation Answer:
25 days


Explanation:

To solve this question, we can apply a short trick approach

Required days = [ D(x1y1) ]
x2y1 + x1y2

x1 = 4 goats, y1 = 6 sheeps and x2 = 2 goats, y2 = 9 sheeps

D = the time taken by x1 and y1 grazing the field = 50 days

By the short trick approach, we get

Required days = [ 50(4 × 6) ]  = 50 × 24  = 50 × 24  = 25 days.
2 × 6 + 4 × 9 12 + 36 48

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MCQ Type: SSC CHSL, Quantitative Aptitude, Work And Time

Q 9.

If 4 men or 8 women can do a piece of work in 15 days, in how many days can 6 men and 12 women do the same piece of work?

A) 
45 days
B) 
15 days
C) 
30 days
D) 
5 days
Answer & Explanation Answer:
5 days


Explanation:

4 men ≡ 8 women

Therefore, 1 men ≡ 2 women

Similarly, 6 men ≡ 12 women

∴     6 men + 12 women ≡ 24 women

Now, applying the chain rule formula, we get

M1D1 = M2D2

M1 = 8 Women, D1 = 15 days and M2 = 24 Women, D2 = ?

D2 = 8 × 15  = 5 days.
24

Hence, option D is correct.

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MCQ Type: SSC CHSL, Work And Time

Q 10.

If A can do a piece of work in 15 days while B can do it in 20 days. If they work on it together for 4 days, then the portion of work that is left is:

A) 
1
4
B)  1/10
C)  7/15
D)  8/15
Answer & Explanation Answer: 8/15

Explanation:
A's 1 day's work = 1 ;
15
B's 1 day's work = 1 ;
20
(A + B)'s 1 day's work = ( 1 + 1 ) = 7 .
15 20 60
(A + B)'s 4 day's work = ( 7 x 4 ) = 7 .
60 15
Therefore, Remaining work = ( 1 - 7 ) = 8 .
15 15

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MCQ Type: SSC CHSL, Work And Time

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